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BIOLOGY WITH HAMZA · MDCAT REVISION

Bioenergetics

Name: ____________________   Date: ______________

Recall first. Check second. Return to the ideas you missed.

Choose “Save as PDF” in your browser’s print dialog to download this chapter sheet.

Learning targets

Core notes

Read, cover and redraw

The energy logic of glycolysis
01Invest

ATP activates a six-carbon sugar.

02Split

One six-carbon molecule becomes two three-carbon units.

03Oxidise

Electrons reduce NAD to NADH.

04Pay off

ATP forms and two pyruvate remain.

The net ATP gain is smaller than the total ATP produced because ATP is consumed in the investment phase.

Written recall

1. Why does blocking the electron-transport chain eventually slow the Krebs cycle?

2. What is the immediate purpose of fermentation?

3. Where are protons pumped?

4. Can ATP form without ATP synthase?

5. Does oxygen consumption alone measure ATP output?

Apply the idea

1. During glycolysis, one glucose molecule leads to the formation of four ATP molecules, while two ATP molecules are invested. What is the net ATP gain from glycolysis of three glucose molecules?

  1. 6 ATP
  2. 2 ATP
  3. 12 ATP
  4. 18 ATP

My answer: _____   Reason: ____________________________________

2. In isolated mitochondria supplied with substrate and oxygen, a treatment produces the pattern below. Which action best explains it?

Relative mitochondrial responses
MeasurementBefore treatmentAfter treatment
Oxygen consumption100150
ATP synthesis10020
  1. Blocking every electron transfer to oxygen
  2. Making the inner membrane more permeable to protons
  3. Removing all respiratory substrate
  4. Increasing the amount of ATP already present

My answer: _____   Reason: ____________________________________

3. Why can muscle cells continue glycolysis for a time when pyruvate is converted to lactate?

  1. Lactate supplies oxygen to mitochondria
  2. Lactate directly produces most cellular ATP
  3. The reaction regenerates NAD⁺ needed in glycolysis
  4. The reaction replaces all enzymes of glycolysis

My answer: _____   Reason: ____________________________________

Answer key

Cover this section while attempting the questions.

Written recall

1. NADH and FADH₂ cannot be efficiently oxidised, so oxidised NAD and FAD become limiting for Krebs-cycle dehydrogenation reactions.

2. To regenerate oxidised NAD, allowing glycolysis and its small ATP yield to continue.

3. From the matrix toward the intermembrane space.

4. Yes, through substrate-level phosphorylation.

5. No. Coupling efficiency also matters.

Applied questions

1. A — The net gain is 4 − 2 = 2 ATP per glucose. Three glucose molecules therefore yield a net six ATP in glycolysis.

2. B — A proton leak dissipates the gradient without ATP synthase. Electron transfer and oxygen use can continue or rise, while ATP synthesis falls.

3. C — Reduction of pyruvate oxidizes NADH to NAD⁺. This supports the oxidation step in glycolysis, allowing its substrate-level ATP formation to continue.